Blue is the normal force. You would also have friction when it moves.
Blue is the normal force. You would also have friction when it moves.
Doing exponents and exponential factors right now.
Hope I can get some helpMy homework it tells me to graph:
f(x) = 4(1/2)^x
I don't know how to graph it so any help would be nice.
Also Reasoning Is y = (-2)^x an exponential function? Justify your answer.
First put in
x = 0
And
x = infinity
Then connect with a curved line.
Very carefully.How the foo do you graph infinite o;
But my point was figure out where the graph ends up with very large values of x, does it level off at some point?, does it become negative? Does it become zero? You probably haven't been exposed to limits yet so don't bother thinking about infinity, just think about how the graph goes with big values of x.
Does TWC support Latex? That would be nice.
a,b,c are non-negative real numbers, a+b+c=2
Prove that (a^2+b^2)(b^2+c^2)(c^2+a^2)<= 2
Eagerly Awaiting Europa Barbarorum II !!!!
Looks like a triangle inequality problem, but the solution is eluding me. Perhaps you could give some more info about the class this is for? Algebra? Pre-Calc? Calculus? What properties of reals, particularly inequalities, have you been studying?
Last edited by lmt96; April 05, 2012 at 07:28 PM. Reason: new assignment
Eagerly Awaiting Europa Barbarorum II !!!!
You might want to be more specific about your range, else that is a false statement. (e.g. 4, 3.9, .1)I have another one if you're interested in.
a,b,c range in [1;4] ; a+b+c =8
Prove that a^2 + b^2 + c^2 <= 26
err... all 3 numbers are locked in [1;4] ; your example has a number out of the range (0.1).
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After making some efforts I think I've made it even a harder problem
a,b,c ranges in [1;4], so:
So we have to prove:
Which is literally, in 3 numbers there must be a number which ranges in [2;3].
It's a harder problem for me![]()
Last edited by lmt96; April 06, 2012 at 08:01 AM.
Eagerly Awaiting Europa Barbarorum II !!!!
Oops, didn't read closely enough.
I think the interval notation usually goes more like [a,b]. [a;b] looks odd to me, but I assumed it was a closed real interval.
I am somewhat suspicious of these problems now. If they are something provided by a student, it's possible they are nothing more than a graphing calculator exercise. When a problem like this is assigned in a class there is usually a substitution or other trick that solves it handily.
I'm sorry.
In my country it's usually [a;b] instead of [a,b] because "1,3" can be a number. (I know you guys use "1.3" for "one point three").
I'm sorry for any misunderstanding. This is my homework by my teacher.
I'm in grade 10 and I haven't seen any inequalities solved by using graphs in my grade.
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Edit:
"in 3 numbers there must be a number which ranges in [2;3]"
This is wrong.for (3.5;3.5;1), there's no number in [2;3] but still in [1;4] and sum = 8
Last edited by lmt96; April 06, 2012 at 11:33 PM.
Eagerly Awaiting Europa Barbarorum II !!!!
Chriscase is right, this is a geometry problem,
they give you 2 shapes:
S1: x+y+z=2
S2: (x^2+y^2)(y^2+z^2)(z^2+x^2) = 2
and by putting the <= you have to prove that when S2 partition the space, S1 is entirely on the right side (aka S1 does not cross S2, but can be tangent in this case)
Butif M(x,y,z) belongs to S1, in this case it can be on either side of S2, so it's impossible to prove it
M(0,0,2) belong to S1 you have 0<=2 and for M(-10,10,2) belong to S1 you don't have 200*104*104 <=2 .
Those problem are usually designed as have one equation really easy to recognaize but not the other. Your job is to make geographic sense of the equation (usually changing x,y,z by their cylindric or spheric coordonates does the trick).
Last edited by John Doe; April 11, 2012 at 09:20 AM.
Uhh....could someone help me (ie tell me the answer) with this (easy?) equation?
(-7s-6t)/3 = (-s-3u)/-2
Thanks.
One equation, three unknowns. What exactly are we supposed to do, call Jesus?
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