# Thread: Need help with science/math schoolwork? Post here!

1. ## Re: Need help with science/math schoolwork? Post here!

So you are using a relational DB and you want to associate multiple names to a given identity. What is the requirement to store multiple names coming from? Why not just pick one?

2. ## Re: Need help with science/math schoolwork? Post here!

My mother for example have had three different last names; a maiden name, a name from first marriage and a name from second marriage. It's useful to store all three, since if one want to find out more about her childhood and ancestry, her maiden name is needed. Some information can be find if one searches on her name from the first marriage. Her third name is what will be carried on and is also the name that most know her as.

I could pick one, that is true, but I feel like there is a lot of interesting data that goes missing. I don't know.

3. ## Re: Need help with science/math schoolwork? Post here!

So wait, is this for geneology?

4. ## Re: Need help with science/math schoolwork? Post here!

Yes, I did say it somewhere

5. ## Re: Need help with science/math schoolwork? Post here!

Ok, sorry for the confusion.

So the basic methodology would be first to look for a published standard information model. I believe GEDCOM is the de facto standard. Then you'd investigate whether there are any reference relational models that implement the standard, or, if you have a mind to try your hand at it, try to write your own. I usually split the difference by trying out a few reference implementations and then modify or roll my own.

6. ## Re: Need help with science/math schoolwork? Post here!

Does anyone here know how to solve this and put it in a simple form?

Edit. Is it just x * y^2? Just played a bit with the numbers.

7. ## Re: Need help with science/math schoolwork? Post here!

I believe you got it just a little bit wrong. I begin from the x in the middle.
(x-8/3)3=x(-8/3)*3=x-8 so you have x-8y8 under the root. The fourth root(?) of this is x-8*(1/4)y8*(1/4)=x-2y2. Now x2*x-2*y2=x2+(-2)*y2=y2

8. ## Re: Need help with science/math schoolwork? Post here!

Thanks edge! However, I am a bit confused right now here: shouldn't x2+(-2) be x0= 1x?

9. ## Re: Need help with science/math schoolwork? Post here!

Originally Posted by Finlander
Thanks edge! However, I am a bit confused right now here: shouldn't x2+(-2) be x0= 1x?
No x0=1 even if x=o

10. ## Re: Need help with science/math schoolwork? Post here!

Alright I see it now, thanks!

11. ## Re: Need help with science/math schoolwork? Post here!

Originally Posted by Finlander
Thanks edge! However, I am a bit confused right now here: shouldn't x2+(-2) be x0= 1x?
No. The exponential of x defines the order of x. So:
1x = x = x1 ≠ x0 = 1.

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